(y^2-4y+1)-(x^2-4x+1)=1+1-1

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Solution for (y^2-4y+1)-(x^2-4x+1)=1+1-1 equation: 


Simplifying
(y2 + -4y + 1) + -1(x2 + -4x + 1) = 1 + 1 + -1

Reorder the terms:
(1 + -4y + y2) + -1(x2 + -4x + 1) = 1 + 1 + -1

Remove parenthesis around (1 + -4y + y2)
1 + -4y + y2 + -1(x2 + -4x + 1) = 1 + 1 + -1

Reorder the terms:
1 + -4y + y2 + -1(1 + -4x + x2) = 1 + 1 + -1
1 + -4y + y2 + (1 * -1 + -4x * -1 + x2 * -1) = 1 + 1 + -1
1 + -4y + y2 + (-1 + 4x + -1x2) = 1 + 1 + -1

Reorder the terms:
1 + -1 + 4x + -1x2 + -4y + y2 = 1 + 1 + -1

Combine like terms: 1 + -1 = 0
0 + 4x + -1x2 + -4y + y2 = 1 + 1 + -1
4x + -1x2 + -4y + y2 = 1 + 1 + -1

Combine like terms: 1 + 1 = 2
4x + -1x2 + -4y + y2 = 2 + -1

Combine like terms: 2 + -1 = 1
4x + -1x2 + -4y + y2 = 1

Solving
4x + -1x2 + -4y + y2 = 1

Solving for variable 'x'.

Reorder the terms:
-1 + 4x + -1x2 + -4y + y2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 4x + -1x2 + -4y + y2 = 0

The solution to this equation could not be determined.

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